Solve all your queries through NCERT Solutions for Class 3 Maths Chapter 14 that are tailor-made to fit your needs. The solutions of Rupees and Paise have been designed by our experienced group of faculty who are extremely well adept to the CBSE curriculum. NCERT Solution of Class 3th Maths Chapter 14 answers all questions about monetary denominations of rupees and paise. Download Rupees and Paise Class 3 NCERT Solutions for a complete insight and enhanced numerical ability.
Access NCERT Solutions for Class 3 Chapter 14 – Rupees and Paise
1: Write the amounts of money shown by the notes and coins.
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Ans: One hundred one rupees
2: Write the amounts of money shown by the notes and coins
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Ans: Seventy-six rupees and seventy-five paise
3: Write the amounts of money shown by the notes and coins.
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Ans: Thirty-five rupees and seventy-five paise
4.
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Ans: Six hundred eighty-four rupees and twenty-five paise
5: Write the amounts of money shown by the notes and coins
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Ans: One hundred seventy-seven rupees and twenty-five paise
6: Shopping
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Ans:
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7. Find out the total cost of:
- One toy giraffe, one copy, and a glass of lemon juice Rs ________
Ans: One toy giraffe, one copy, and a glass of lemon juice Rs 14.5014.50
- One glass of milk, one packet of biscuits and a banana Rs ________
Ans: One glass of milk, one packet of biscuits, and a banana Rs9.509.50
- One notebook, two pencils and two erasers ________
Ans: One notebook, two pencils, and two erasers Rs 1212
- Two tops, three toffees and two bananas ________
Ans: Two tops, three toffees, and two bananas Rs 8.508.50
8. What can you buy if you have a twenty-rupee note?
- 1 toy car, 1 lemon juice, 1 banana
- ______________, ______________, ________________
Ans: 2 balls =2×7=14rupees=2×7=14������.
1 packet of biscuits =1×4.50=4.50rupees=1×4.50=4.50������.
1 eraser =1×1=1rupees=1×1=1������
- ______________, ______________, ________________
Ans: 1 toy car =1×5=5rupees=1×5=5������.
4 pencil =4×2.50=10rupees=4×2.50=10������.
4 toffees =4×0.5=2rupees=4×0.5=2������.
- ______________, ______________, ________________
Ans: 3 glasses of milk =3×3.5=10.5rupees=3×3.5=10.5������.
3 bananas =3×1.5=4.5rupees=3×1.5=4.5������.
1 notebook =1×5=5rupees=1×5=5������.
- ______________, ______________, ________________
Ans: 4 toffees =4×0.5=2rupees=4×0.5=2������.
2 doll=2×8=16rupees=2×8=16������.
2 erasers =2×1=2rupees=2×1=2������
9. You need to make a cash memo for the things you bought.
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Before adding, first guess how much money will be needed. Then find the total and check your guess. Monu prepared the following cash memos: Check the cash memos and correct them if you find a mistake.
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Add the following:
- Rs.12.50��.12.50
+Rs.13.00−−−−−−−−−+��.13.00_
b) Rs.55.50��.55.50
+Rs.14.00−−−−−−−−−+��.14.00_
c) Rs.30.00��.30.00
+Rs.31.50−−−−−−−−−+��.31.50_
Subtract the following
- Rs.25.50��.25.50
−Rs.11.50−−−−−−−−−−��.11.50_
b) Rs.103.50��.103.50
−Rs.62.00−−−−−−−−−−−��.62.00_
c) Rs.19.50��.19.50
−Rs.7.00−−−−−−−−−−��.7.00_
Ans: As per my guess, the total amount of the cash memo would be around Rs 70.
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The total amount of cash memo= Rs 67.50, and our guess was of almost the same amount i.e. Rs 70.
The corrections in the cash memo, prepared by Monu is shown below
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Adding we have
(a) Rs.12.50��.12.50
+Rs.13.00−−−−−−−−−+��.13.00_
25.5025.50
b) Rs.55.50��.55.50
+Rs.14.00−−−−−−−−−+��.14.00_
69.5069.50
c) Rs.30.00��.30.00
+Rs.31.50−−−−−−−−−+��.31.50_
61.5061.50
Subtracting
(a) Rs.25.50��.25.50
−Rs.11.50−−−−−−−−−−��.11.50_
14.0014.00
b) Rs.103.50��.103.50
−Rs.62.00−−−−−−−−−−−��.62.00_
41.5041.50
c) Rs.19.50��.19.50
−Rs.7.00−−−−−−−−−−��.7.00_
12.5012.50
10. You have 30 rupees with you. Find out how much money will be left after buying the following items:
- One ball, one doll and one toy giraffe Total cost _________. Money left _________.
Ans: One ball
=Rs.7=��.7
, one doll
=Rs.8=��.8, one toy giraffe =Rs.6.50=��.6.50.
Total cost
=Rs.7+Rs.8+Rs.6.50=Rs.21.50=��.7+��.8+��.6.50=��.21.50
Money left
=Rs.30−Rs.21.50=Rs.8.50=��.30−��.21.50=��.8.50
- Two bananas, one pack of biscuits and two glasses of lemon juice. Total cost _________. Money left _________.
Ans: Two bananas
=Rs.3=��.3
, one pack of biscuits
=Rs.4.50=��.4.50, two glasses of lemon juice =Rs.6=��.6.
Total cost
=Rs.3+Rs.4.50+Rs.6=Rs.13.50=��.3+��.4.50+��.6=��.13.50
Money left
=Rs.30−Rs.13.50=Rs.16.50=��.30−��.13.50=��.16.50
- Three notebooks, two pencils and two erasers. Total cost _________. Money left _________.
Ans: Three notebooks
=Rs.15=��.15
, two pencils
=Rs.5=��.5, two erasers =Rs.2=��.2.
Total cost
=Rs.15+Rs.5+Rs.2=Rs.22=��.15+��.5+��.2=��.22
Money left
=Rs.30−Rs.22=Rs.8=��.30−��.22=��.8
11: Three friends wanted to buy a cricket bat and ball. Bina had Rs 48.50, Raman had Rs 55.50 and Venu had Rs 38.00 How much money did they have in all?
Ans: Bina has
Rs.48.50��.48.50
Raman has
Rs.55.50��.55.50
Venu has
Rs38.00��38.00
The total amount they have altogether is Rs48.50+Rs55.50+Rs38.00��48.50+��55.50+��38.00 which is equal to
Rs142��142
.
12: Hari booked a railway ticket for Rs 62.50. He gave a 100-rupee note. How much money will he get back with the ticket?
Ans: Cost of a railway ticket =Rs62.50=��62.50
Hari gave Rs100��100 note Change he should get back =100.00−62.50=37.50=100.00−62.50=37.50
100.00−62.50−−−−−−−37.50100.00−62.50_37.50
Hence, Hari will get Rs 37.50 back with the ticket.
13: Gita and her friends went shopping. She bought things for Rs 58, Rs 37 and Rs 22. Gita had a hundred-rupee note. How much money should she borrow from her friends to pay the bill?
Ans: Amount Geeta spent on shopping =Rs58+Rs37+Rs22=��58+��37+��22
58+37+22−−−−11758+37+22_117
Thus, Gita spent Rs 117 on shopping. If Gita had Rs 100 with her then she needs to borrow Rs117−Rs100=Rs17��117−��100=��17 from her friends.
117−100−−−−017117−100_017
Thus, Gita needs to borrow Rs 17 from her friends.
14:
| Mumbai News Children Freed from Factory10 young children working in a bangle factory were set free today. A news reporter and the police found them in a sad condition. The factory made the children work very hard. It paid them only Rs 20 a day. The children are happy to go back to their homes in their village. They will go to a special school so that they can learn to study like other children their age. By making children work, the factory tries to save money. The police will now take action. |
Let us see how much money the factory tries to save.
Money 1 older worker should get =Rs513=��513
A day Money 1 child is paid =Rs80=��80
A day on 1 person the factory saves Rs513−____=Rs433��513−____=��433 a day
On 10 persons the factory saves Rs433×10=��433×10= Rs ______ a day
Ans:
Money 1 older worker should get =Rs513=��513
A day Money 1 child is paid =Rs80=��80
A day on 1 person the factory saves Rs513−80=Rs433��513−80=��433 a day
On 10 persons the factory saves Rs433×10=Rs4330��433×10=��4330 a day
Train Journey
15. This train goes from New Jalpaiguri to Guwahati. One its way, it stops at New Mal, Alipurduar and Goalpara stations. The cost of a rail ticket to different stations is given in the table.
| Distance from New Jalpaiguri (in km) | Station | Fare (in Rs) |
| 57 | New mal | 12.50 |
| 175 | Alipurduar | 28.00 |
| 366 | Goalpara | 49.50 |
| 495 | Guwahati | 62.50 |
Find the distance:
- From New Mal to Guwahati ____________
Ans: From mal to Guwahati =495km−57km=438km=495��−57��=438��
- Between New Mal and Goalpara ___________
Ans: Between New Mal and Goalpara =366km−57km=309km=366��−57��=309��
- From Alipurduar to Guwahati ____________
Ans: From Alipurduar to Guwahati =495km−175km=320km=495��−175��=320��
- Between New Mal and Alipurduar ___________
Ans: Between New Mal and Alipurduar =175km−57km=118km=175��−57��=118��
- From Goalpara to Guwahati ___________
Ans: From Goalpara to Guwahati =495km−366km=129km=495��−366��=129��
16: Find the cost of tickets:
- Bhupen is going from New Jalpaiguri to Alipurduar. What is the cost of his ticket?
Ans: The cost of the ticket is 28 rupees.
- Indira has to go from New Jalpaiguri to Goalpara. How much does she pay for the ticket?
Ans: Rupees 49.50 has to be paid for the tickets.
- Debu, Shoma and Gobind are going from New Jalpaiguri to New Mal. What amount will they pay for three tickets? They give a Rs 50 note for the tickets. How much money will they get back?
Ans: The distance between New Jalpaiguri to New Mal is 57 Km.
Since there 3 members, the amount they pay for the tickets
=3×Rs12.50=Rs.37.50=3×��12.50=��.37.50
Amount of money that they get back
=Rs50−Rs37.50=Rs12.50=��50−��37.50=��12.50
NCERT Solutions Class 3 Maths Chapter 14 – Free PDF Download
It is crucial for a student to be well versed in mathematics to sharpen their creativity and abstract thinking. The syllabus of NCERT Class 3 mathematics has chapters that induce great problem-solving ability with real-life examples. The solutions for Class 3 Maths Chapter 14 Rupees and Paise should be highly taken into consideration for practice during the examination. In order to be confident about your concepts download free pdf for Class 3 Chapter 14 Solution for NCERT Maths.
A Quick Overview of Class 3 Maths Chapter 14 Rupees and Paise
The Class 3 Maths Chapter 14 Rupees and Paise give the student the idea of money. The chapter teaches about the types of notes and coins used in daily life. Download NCERT Solutions for Class 3 Maths Chapter 14 Rupees and Paise which gives you a detailed practice and clear vision of the topic.
In this chapter, one can get a detailed explanation of the relation between rupees and paise. NCERT Chapter 14 Rupees and Paise also introduces the students to all the denominations of notes and coins. It also contains word problems including addition and subtraction of money to make the students familiar with everyday calculations. The Class 3 Maths Ch 14 NCERT Solutions contain the answer to all the questions regarding money with logical reasoning for each. The CBSE Class 3 Maths Chapter 14 Solutions contain the following solved exercises.
| Maths Class 3 Chapter 14: Exercises |
| Page 192-193: Money Game |
| Page 194-197: Shopping |
| Page 197-198: Practice Time |
| Page 198: Find Out |
| Page 199-200: Train Journey |
Benefits of NCERT Solutions For Class 3 Maths By Study Studio
NCERT Solutions For Class 3 Maths by Study Studio is the point of reference for those students planning to ace competitive examinations like Olympiads as well as school curriculum. The study material is unique in many ways:
- Eminent educators have provided answers to all the questions of the textbook.
- It develops a thorough understanding of the Rupees and Paisa concept.
- It is prepared according to the CBSE syllabus.
- 100% accurate answers with detailed reasoning.
- Shortcut tips and chapter insights for cracking examinations are also given.
- Definitions and formulae for easy revision can be found.
- A chronological approach towards problem-solving has been taken.
The specially designed NCERT Solutions for Class 3 Maths Chapter 14 Rupees and Paise addresses all doubts of the students.
Important Questions and Answers of Ch 14 Class 3 Maths
1. What is the Importance of Maths Class 3 Chapter 14 in the Curriculum?
Ans. From this chapter, Class 3 students deepen their understanding of value money that takes an important place in the mathematics curriculum. This chapter teaches kids the value of coins and notes for not only buying or selling but also for wage and work etc. The lesson features targeted instruction and helpful exercises that provide practical real-life examples for students.
2. You go to a toy shop with Rs100. The shopkeeper tells you the price of the following toys:
- A car: Rs20
- A ping pong ball: Rs10
- A doll: Rs15
- A robot: Rs30
You buy 1 car, 1 doll, 1 robot, and 2 ping pong balls. What will be the total bill?
Ans: Here is the bill:
| Serial No. | Toy | Price of 1 toy in Rs | Amount spent in Rs |
| 1 | car | 20 | 20 |
| 2 | doll | 15 | 15 |
| 3 | ping pong ball | 10 | 10 X 10 = 20 |
| 4 | robot | 30 | 30 |
| Total | 85 |
The toys will cost Rs85 in total.
3. How much money will be left with me?
Ans. I was carrying Rs100 with me.
I spent Rs85 to buy toys.
Now, I have Rs(100 – 85) = Rs15 left with me.
4. Three friends Rahul, Priya, and Ali wanted to buy a badminton set. Rahul had Rs200, Priya had Rs 450, and Ali had Rs775 with him. How much money did they have altogether?
Ans. Amount of money that the three friends had in all = Rs (200 + 450 + 775) = Rs1425.
5. If the price of the badminton set was Rs1600. How much money did they need more?
Ans. They needed Rs(1600 – 1425) = Rs175 more to buy the badminton set.
You need to practise more of such sums to gain confidence in money maths. Download your copy of Rupees and Paise Class 3 NCERT Solutions by Study Studio and get access to a wide range of solved problems.