NCERT Solutions for Class 4 Maths Chapter 6 - Junk Seller teaches you the basics of multiplication through a story of a young woman, Kiran who is a Junk Seller. The main objective of this lesson is to teach students how we can multiply things not only in actions but also in our thoughts. Our main goal is to keep multiplying what we have in our hands so that we are never standstill. The NCERT Solutions for Class 4 Maths Chapter 6 - Junk Seller are available in the PDF format on Study Studio, and students can download them for free. ch6-Download Access NCERT Solution for Class 4 Mathematics Chapter 6 -The Junk Seller 1. What about you? Do you also find Maths difficult? Ans: No, Math is not difficult for me. If one is practised well then math is very easy. What is the most difficult thing in your Maths books? ________ Ans: There is nothing very difficult if someone practised well in math book. What do you think is the easiest lesson? ________ Ans: Addition is the easiest process in math as it was practised so many times. 2. Find out: how much for a cup of tea? Ask people and find out the cost of a cup of tea at a tea stall ___________ at a hotel _______________ Ans: The price is different in different places as the quality is different and the serving style is also different. At a tea stall a cup of tea costs Rs 10. At a hotel a cup of tea costs Rs 20. 3. If a person who runs a tea stall earns Rs 30 in a day, how much will he earn in 10 days? _____________ And in a month? _______________ How did you get the answer? Discuss. Ans: If a person who runs a tea stall earns Rs 30 in a day then in 10 days he will earn ten times of one day that is the amount of money earned =Rs. 30×10=��. 30×10 =Rs. 300=��. 300 A month has 30 days. If the person earns Rs 30 in a day then in 30 days he will earn, 30×30=Rs. 90030×30=��. 900 4. Hariya and Babu want to buy a handcart for Rs 300. Hariya has taken a loan of Rs 300 from a bank for six months. He will pay Rs 51 every month to the bank. But I have taken a loan of Rs 300 from Chunnilal. After six months I will pay back Rs 360. Who has to pay back more — Hariya or Babu? _____________ Ans: If Hariya has to pay Rs 51 every month for 6 months then, The total amount paid by Hariya =Rs. 51×6=��. 51×6 =Rs. 306=��. 306 Thus, Hariya has paid a total Rs 306 in 6 months to the bank. Whereas Babu has to pay Rs 360 after 6 months to Chunnilal. Thus, Hariya paid 6 Rs more than what he has taken again Babu has paid Rs 60 more than what he taken. So that means Babu has to pay more. 5. I have 9 rickshaws of my own. I give the rickshaws on rent. each for Rs 20 a day. On Sundays I do not take any money for them. In a week how much does Kiran earn from one rickshaw? Ans: If Kiran doesn’t take any money from the Rickshaw on Sundays, then in a week, he gives the rickshaw on rent and earn for 6 days. Rent earned from one Rickshaw is Rs 20 per day. Rent earned to Kiran from one rickshaw in 6 days =Rs. 20×6=��. 20×6 =Rs. 120=��. 120 Thus, in a week Kiran earns Rs 120 from one Rickshaw. 6. Do it mentally and write the answers. 2×6=2×6= __________ Ans: We do it in the following manner: 2 times 6 is 12 that is 2×6=122×6=12 20×6=20×6=__________ Ans: We do it in the following manner: 20 times 6 is 120 that is 20×6=12020×6=120 2×60=2×60=__________ Ans: We do it in the following manner: 2 times 60 is 120 that is 2×60=1202×60=120 3×42=3×42=__________ Ans: We do it in the following manner: 3 times 42 is 126 that is 3×42=1263×42=126 4×80=4×80=__________ Ans: We do it in the following manner: 4 times 80 is 320 that is 4×80=3204×80=320 4×81=4×81=__________ Ans: We do it in the following manner: 4 times 81 is 324 that is 4×81=3244×81=324 9×25=9×25=__________ Ans: We do it in the following manner: 9 times 25 is 225 that is 9×25=2259×25=225 31×9=31×9=__________ Ans: We do it in the following manner: 31 times 9 is 189 that is 31×9=27931×9=279 7. Look up the rate list to see today’s rates. Help Kiran to find out the cost of the junk. How much will Kiran pay for 31 kg newspaper?1 kg newspaper costs Rs 5. 30 kg cost Rs 5×305×30= Rs 150. So, for 31 kg she pays Rs _____. Ans: 1 kg newspaper= Rs. 51 �� newspaper= ��. 5 Cost of 31 kg newspaper is 5 times of 31 that is 31×5=Rs. 15531×5=��. 155 How much will Kiran pay for 42 kg newspaper? Ans: 1 kg newspaper= Rs. 51 �� newspaper= ��. 5 Cost of 42 kg newspaper is 5 times of 42 that is 42×5=Rs. 21042×5=��. 210 Also find the cost of: (a) 22 kg of plastic (b) 23 kg of waste paper (c) 12 kg of iron Rate-List Kind of Junk Price of 1 Kg Waste Paper Rs 4/- Newspaper Rs 5/- Iron Rs 12/- Brass Rs 170/- Plastic Rs 10/- Can you do this without writing? Guess the total money Kiran will pay to the junk collectors. Will it be — More than 600? — Less than 600? Ans: 1 kg plastic= Rs. 101 �� plastic= ��. 10 Cost of 22 kg plastic = 22 × Rs 10 = Rs 22022 × �� 10 = �� 220 1 kg waste paper costs Rs 4. Thus, 23 kg waste paper will cost Rs 4 × 23 = Rs 92�� 4 × 23 = �� 92 1 kg iron costs Rs 12. So, 12 kg iron will cost Rs 12 × 12 = Rs 144�� 12 × 12 = �� 144 Add the numbers in the box 100+20+20+4=144100+20+20+4=144 Total money Kiran paid to junk collectors will be =Rs 155 + Rs 210 + Rs 220 + Rs 92 + Rs 144=�� 155 + �� 210 + �� 220 + �� 92 + �� 144 =Rs. 821=��. 821 So, the total money paid to the junk seller is 821 which is more than Rs 600. 8. Kiran bought 1 kg plastic for Rs 10, but sold 1 kg plastic for Rs 12. How much money does she earn on selling 1 kg of plastic? Rs _______ So, how much money does she earn for 63 kg? Rs _______ Ans: 1 kg plastic= Rs. 101 �� plastic= ��. 10 Cost of 1 kg plastic is 12 Rs From 1 kg plastic she earns a profit of =Rs. (12−10)=Rs. 2=��. (12−10)=��. 2 Thus, from 63 kg plastic she gets a profit of =Rs 2×63=Rs 126=�� 2×63=�� 126 Kiran would make Rs 126 on the sale of 63 kg of plastic. 9. How much money will Dinu pay for 32 kg iron? Kiran buys 1 kg of iron for Rs 12 but sells it for Rs 14. How much does she earn when she sells 32 kg iron? Rs _______ Ans: Cost of 1 kg Iron is Rs 14. Hence, 32 kg iron costs Rs 14×32=Rs 448�� 14×32=�� 448 We do it like this, 1043030×10=30030×10=30030×4=12030×4=120210×2=2010×2=202×4=82×4=8 Add the numbers in the box 300+120+20+8=448300+120+20+8=448 So, Dinu needs to paid Rs 448 for 32 kg iron. The cost of 1 kilogramme iron for Kiran is Rs 12, while the selling price is Rs 14. The profit made on selling 1 kilogramme iron is =Rs. (14−12)=Rs. 2=��. (14−12)=��. 2 She earned 2×32=Rs. 642×32=��. 64 by selling 32 kg of iron. Therefore, on selling 32 kg iron Kiran earns Rs 64. 10. I bought 1 kg newspaper for Rs 5, but sold it for Rs 6. How much money did I earn by selling 152 kg of newspaper? ________ Ans: 1 kg newspaper= Rs. 51 �� newspaper= ��. 5 Amount received on selling 1 kg of newspaper = Rs 6 On selling 1 kg newspaper the profit earned =Rs (6 −5)=Re 1=�� (6 −5)=�� 1 On selling 152 kg newspaper the profit earned Rs. 152×1=Rs. 152��. 152×1=��. 152 On selling 152 kg of newspaper Kiran the total amount earned Rs 152. 11. How much money will Dinu pay for 4 kg brass? _________ Guess the answer first. Ans: Cost of 1 kg brass is Rs 180 Thus, cost of 4 kg brass is, Rs. 4×180=Rs. 720��. 4×180=��. 720 We will do it as follows 1008024×100=4004×100=4002×80=3202×80=320 Add the numbers given in the box to get the result, 400+320=720400+320=720 Dinu will therefore pay Rs 720 for 4 kilogram brass. 12. First guess the answer and then calculate: a) 37×18=37×18= Ans: 3071030×10=30030×10=30010×7=7010×7=70830×8=24030×8=2408×7=568×7=56 Add the numbers given in the box to get the result, 300+240+70+56=666300+240+70+56=666 b) 45×24=45×24= Ans: 4052020×40=80020×40=80020×5=10020×5=10044×40=1604×40=1604×5=204×5=20 Add the numbers given in the box to get the result, 800+100+160+20=1080800+100+160+20=1080 c) 69×52=69×52= Ans: 6095060×50=300060×50=300030×4=12030×4=120210×2=2010×2=202×4=82×4=8 Add the numbers given in the box to get the result, 3000+450+120+18=35883000+450+120+18=3588 d) 77×55=77×55= Ans: 100402300×3=900300×3=90040×5=20040×5=2005×2=105×2=10 Add the numbers given in the box to get the result, 3150+350+350+35=42353150+350+350+35=4235 e) 142×5=142×5= Ans: 30080230×10=30030×10=30080×3=24080×3=2403×2=63×2=6 Add the numbers given in the box to get the result, 500+200+10=710500+200+10=710 f) 382×3=382×3= Ans: 30080230×10=90030×10=90080×3=24080×3=2403×2=63×2=6 Add the numbers given in the box to get the result, 900+240+6=1146900+240+6=1146 g) 2×175=2×175= Ans: 1007052×100=2002×100=2002×70=1402×70=1402×5=102×5=10 Add the numbers given in the box to get the result, 200+140+10=350200+140+10=350 h) 4×206=4×206= Ans: 20064×200=8004×200=8004×6=2404×6=240 Add the numbers given in the box to get the result, 800+24=824800+24=824 13. Later she paid Rs 919 to the junk collectors. When she sold the junk, she got these notes and coins from Dinu. 28 coins of 5, 5 notes of 100, 1 note of 50, 18 notes of 10, 9 notes 20 Now you make a record in her diary. Find out how much she earned this time. Ans: Money, I paid is Rs. 919 Money, I got – Rs 500 Rs 50 Rs 180 Rs 140 Total Rs 1050 The amount I earned = Total amount – amount paid Rs 1050 Rs 919 Money, I earned Rs 131 We do it as follows: 5 notes of 100 rupee 5×100=Rs 5005×100=�� 500 1 note of 50 rupee 1×50=Rs 501×50=�� 50 18 notes of 10 rupee 18×1=1818×1=18 18×10=Rs 18018×10=�� 180 9 notes of 20 rupee 9×2=189×2=18 9×20=Rs 1809×20=�� 180 28 coins of 5 rupee 20 × 5 = 10020 × 5 = 100 8×5=408×5=40 100+40=140100+40=140 28×5=Rs 14028×5=�� 140 Money, I got is the sum of the total money that is, Rs 500+Rs 50+Rs 180+Rs 180+Rs 140 =Rs 1050�� 500+�� 50+�� 180+�� 180+�� 140 =�� 1050 Money, I earned is the remaining what I paid from the total money I got that is, Rs 1050−Rs 919=Rs 131�� 1050−�� 919=�� 131 NCERT Solutions for Class 4 Maths Chapter 6 - The Junk Seller - Free PDF Download Kiran was a very poor woman. She got married at a very young age. She wanted to start a business for selling junk. She took a loan of Rs. 8000 to start her business, and after that, her lifestyle changed completely. You know how to multiply a number by a one-digit or a two-digit number. You know that 5 × 12 = 60. Let us quickly revise the properties of multiplication. 1. When we multiply two numbers, the order in which we multiply them does not matter. The result or product remains the same. Example: 6 × 5 = 30; 5 × 6 = 30. So you see, whichever way we are multiplying, the answer is the same. 2. Whenever you multiply a number with 0, the answer is always a 0. Example: 7 × 0 = 0; 0 × 0 = 0. 3. When a number is multiplied by 1 then the result or the product is the number itself. Example: 6 × 1 = 6; 1 × 6 = 6; 1 × 1 = 1 4. When you multiply three numbers, you can group them in any order. The result is always the same. Example: 43 × 19 × 28 = 19 × 43 × 28 = 22,876 Now, let us go through the real-life applications of multiplication. Let us consider an example. You go to a shop to buy chocolate. One chocolate costs Rs. 50. You want to buy 4 chocolates. So how much will you pay the shopkeeper? Solution: Cost of 1 chocolate = Rs. 50 Cost of 4 chocolates = Rs. (50 × 4) = Rs. 200 you are multiplying Rs.50 four times What do You Mean by Loan? A loan is a type of credit that a bank or any other financial institution lends to a person with an agreement of future repayment of the amount. The borrower borrows a certain amount of money from the lender and then returns the amount with some extra money, which is called interest, in a fixed number of days. So if you borrow Rs. 300 from a bank and you promise to pay back Rs.60 every month for 6 months. How much do you pay after 6 months? Rs. 60 × 6 months = Rs. 360. How much extra money are you paying after 6 months? I am paying Rs. 60 extra. This extra amount is called Interest. Let me tell you another concept of the Estimation of the product of 2-digit numbers. This will help you in solving the exercises in NCERT Solutions Maths Chapter 6. The method of estimating the product of 2-digit numbers is as follows. Round-off each number to the nearest 10. It is then easy to multiply the numbers mentally to get the estimate. Then, you can add the products of the numbers to get the result. Benefits Of NCERT Solutions for Class 4 Maths Chapter 6 - The Junk Seller The benefits of NCERT Solutions for Class 4 Maths Chapter 6 - The Junk Seller are manifold. Firstly, they provide a comprehensive and structured approach to learning mathematics at the elementary level. Through the engaging story of the junk seller, students not only grasp mathematical concepts but also learn valuable life lessons about resourcefulness and hard work. These solutions are designed to enhance problem-solving skills by presenting mathematical challenges in a relatable context. Moreover, NCERT Solutions are aligned with the curriculum, ensuring that students receive a strong foundation in maths, which is essential for their academic growth. They also encourage independent learning as students can practise and revise concepts at their own pace. Overall, NCERT Solutions for Chapter 6 play a crucial role in making mathematics enjoyable, accessible, and relevant for young learners. Conclusion The NCERT Solutions for Class 4 Maths Chapter 6 - The Junk Seller provides a valuable educational resource for young learners. This chapter not only introduces students to basic mathematical concepts but also imparts important life lessons. Through the story of the junk seller, children learn about the importance of hard work, resourcefulness, and the value of every item, no matter how insignificant it may seem. The solutions offered in this chapter are meticulously designed to engage students and enhance their problem-solving skills. By combining maths with real-life scenarios, NCERT has created a well-rounded learning experience that encourages critical thinking and practical application. These solutions are undoubtedly a crucial tool in nurturing a strong mathematical foundation in young minds.